📊 Averages & Mixtures: UGC NET Mastery Guide
Crack 3-5 questions/year with these data interpretation and problem-solving techniques. Includes alligation method, weighted averages, and real NET exam patterns.
🔑 Core Formula:
Average = Sum of Observations / Number of Observations
Key Variations:
Key Variations:
- Total Sum = Average × Number of items
- New Average when adding/removing items
- Weighted Average = (w₁x₁ + w₂x₂) / (w₁ + w₂)
1. Averages: Advanced Concepts
🔹 NET Exam's Favorite Average Problems
Type | Solution Approach | Example |
---|---|---|
Missing Data | Use total sum concept | Avg of 4 tests=80. First 3=85,76,72. Find 4th test? Total=320 → 4th=320-(85+76+72)=87 |
Inclusion/Exclusion | Adjust total sum and count | Class avg=40 for 30 students. If 2 leave, new avg=42. Find avg of departed students? Original total=1200 → New total=28×42=1176 → Departed sum=24 → Avg=12 |
Weighted Average | Account for different group sizes | Group A (10 people, avg=50) + Group B (20 people, avg=70) Combined avg=(10×50 + 20×70)/30=63.33 |
📚 NET 2021 Question Analysis:
"A researcher's average publication is 2.5 papers/year for first 6 years and 3.2 papers/year for next 4 years. What's the overall average?"
Solution:- First period total = 6 × 2.5 = 15 papers
- Second period total = 4 × 3.2 = 12.8 papers
- Overall average = (15 + 12.8) / 10 = 2.78 papers/year
2. Mixtures: The Alligation Method
📌 Understanding Cheaper vs. Dearer in Alligation
Cheaper Component (C):
- The ingredient with lower value (price/percentage/strength)
- Example: In mixing ₹30/kg and ₹60/kg rice, ₹30 is cheaper
- In acid solutions: 20% concentration is cheaper than 40%
Dearer Component (D):
- The ingredient with higher value
- Example: In same rice problem, ₹60 is dearer
- In medications: 80% pure drug is dearer than 50% diluted version
💡 Key Rule: Alligation always compares how much each component deviates from the desired mixture (M):
Ratio = (D - M) : (M - C)
Ratio = (D - M) : (M - C)
⚖️ Visual Alligation Technique
⚖️ Interactive Alligation Diagram
Cheaper
(C=₹30)
(C=₹30)
Mixture
(M=₹50)
(M=₹50)
Dearer
(D=₹60)
(D=₹60)
Ratio = (60-50) : (50-30) = 10:20 = 1:2
- Cheaper Quantity / Dearer Quantity = (D - M) / (M - C)
- Where: C = Cheaper item value, D = Dearer item value, M = Mixture value
Ratio = (70-55):(55-40) = 15:15 = 1:1
🔹 Mixture Problem Types
Scenario | Approach | NET Exam Frequency |
---|---|---|
Two-item mixtures | Direct alligation | High (2-3/year) |
Three+ items | Step-wise alligation | Medium (1/year) |
Replacement | Fraction replacement concept | Low (Every 2 years) |
Advanced Mixture Formula:
New concentration = 20%(8/10) + 100%(2/10) = 16% + 20% = 36%
When x liters are replaced from V liters of solution with C₁ concentration to C₂ concentration:
Final Concentration = C₁(1 - x/V) + C₂(x/V)
Example: 10L of 20% alcohol. If 2L replaced with pure alcohol:New concentration = 20%(8/10) + 100%(2/10) = 16% + 20% = 36%
3. Combined Averages & Mixtures
🧪 NET 2022 Case Study:
"A lab mixes three acid solutions: 20% (5L), 30% (10L), and 40% (15L). Calculate: (a) Overall concentration (b) How much 50% solution to add for 35% mix?"
Solution:- Weighted average:
(20×5 + 30×10 + 40×15) / (5+10+15) = (100+300+600)/30 = 33.33% - Alligation method:
Existing (33.33%) + New (50%) → Target (35%)
Ratio = (50-35):(35-33.33) = 15:1.67 ≈ 9:1
For 30L existing, add (30×1)/9 ≈ 3.33L
🔍 Data Interpretation Shortcut
When NET gives tabular data:Batch | Quantity | Purity% |
---|---|---|
A | 200g | 65% |
B | 300g | 80% |
- Total pure substance = (200×0.65) + (300×0.8) = 130 + 240 = 370g
- Total mixture = 500g
- Overall % = 370/500 × 100 = 74%
4. NET Exam Practice Arena
Level 1: Direct Formulas (1 min each)
- Class avg=42 for 25 students. If teacher's score (58) included, new avg? (Ans: (1050+58)/26=42.62)
- In what ratio mix ₹30/kg and ₹50/kg rice for ₹45/kg? (Ans: (50-45):(45-30)=5:15=1:3)
- Average age of 10 researchers is 32. When 2 leave, avg increases by 3. If one departed is 25, find the other's age. (Ans: Original total=320 → New total=8×35=280 → Departed sum=40 → Other=40-25=15)
- Solution A (40% salt, 100ml) mixed with B (60% salt, 150ml). If 50ml of mix replaced with pure water, final concentration? (Ans: Initial mix=(40+90)/250=52% → After replacement=52%(200/250)+0%(50/250)=41.6%)
🧠 Memory Anchors
Alligation Mnemonic: "Dear Minus Cheap" (D - M / M - C)Average Trap: "Adding higher value → Avg ↑" (and vice versa)
Mixture Rule: "The middle value is always closer to larger quantity"
🚀 Exam Strategy
Situation | Action | Time Save |
---|---|---|
Complex averages | Assume base value (e.g., 100) | 30-40 seconds |
Decimal heavy calcs | Multiply all terms by 10/100 | Prevents errors |
Verification needed | Check with extreme values | 1 min sanity check |
💡 Pro Tip: For replacement problems, remember x/V remains constant - if 20L out of 100L replaced (1/5), then next replacement of 20L from new 100L still replaces original (1/5)² quantity.